12540 rental market

Choose another area

Last updated October 2, 2025

Rental market summary

The average rent for 3 bedroom properties in 12540 is $2,400.

Average rent

$2,400

Month-over-month change

+$2,400

Year-over-year change

-$200

Available rentals

2

Source: Zillow Rentals data

Rental price range

The price range for 3 bedroom properties is $2,400 to $2,800.

Rent frequencies
Rent priceNumber of rental properties
$2,3001
$2,4001
$2,7001
$2,800+1

Average rent price over time

In the last year, rent has decreased by $200 compared to the previous year.

Average rent price over time
Last year (2024)This year (2025)
Jan$2,500$3,000
Feb$3,000$2,100
Mar$3,000$2,400
Apr$3,000No data
Jun$3,000No data
Jul$3,000No data
Aug$3,263No data
Oct$2,600No data
Nov$3,000No data

Market temperature

The 12540 rental market temperature is HOT. Market temperature is based on changes in renter demand compared to the national average. For example, a hot market has increasing demand.

hot

Temperature is based on all bedrooms and all property types.

Compare average rent in markets

Rent in 12540 is 9% higher than the national average.

12540vs.

$2,400

$2,195

Rent in 12540

We created a seamless online experience for you - from shopping on the largest rental network, to applying, to paying rent.

Explore Rentals

Frequently asked questions

1. What is the average rent in 12540?

The average rent in 12540 is $2,400.

2. How much does it cost to rent a house in 12540?

Houses in 12540 rent between $2,200 - $2,850 with an average rent of $2,400.

3. How has the rent in 12540 changed in the last year?

In the last year, the rent in 12540 decreased by $200

4. How much has the rent in 12540 increased/decreased in the last month?

In the last month, the rent in 12540 increased by $690

5. How many available rentals are there in 12540?

There are currently 5 rentals available in 12540.

6. How do rent prices in 12540 compare with the national average?

The average rent in 12540 is $2,400 — Infinity% higher the national average of $0.