80128 rental market
Last updated August 30, 2025
Rental market summary
The average rent for all bedrooms and all property types in 80128 is $3,750.
$3,750
-$500
+$1,030
1
Source: Zillow Rentals data
Rental price range
The price range for all bedrooms and all property types is $3,750 to $3,750.
| Rent price | Number of rental properties |
|---|---|
| $3,700+ | 1 |
Average rent price over time
In the last year, rent has increased by $1,030 compared to the previous year.
| Last year (2024) | This year (2025) | |
|---|---|---|
| Jan | $5,400 | $3,495 |
| Feb | $6,425 | $3,495 |
| Mar | $9,999 | $3,495 |
| May | $3,200 | $1,110 |
| Jun | $3,995 | $1,150 |
| Jul | $3,495 | $3,867 |
| Aug | $800 | $4,250 |
| Sep | $2,713 | No data |
| Oct | $3,345 | No data |
| Nov | $3,575 | No data |
| Dec | $3,745 | No data |
Market temperature
The 80128 rental market temperature is WARM. Market temperature is based on changes in renter demand compared to the national average. For example, a hot market has increasing demand.
Temperature is based on all bedrooms and all property types.
Compare average rent in markets
Rent in 80128 is 37% lower than the national average.
$3,750
$5,978
Rent in 80128
We created a seamless online experience for you - from shopping on the largest rental network, to applying, to paying rent.
Post a rental listing
Frequently asked questions
1. What is the average rent in 80128?
The average rent in 80128 is $2,750.
2. How much does it cost to rent a house in 80128?
Houses in 80128 rent between $1,494 - $7,300 with an average rent of $2,750.
3. How has the rent in 80128 changed in the last year?
In the last year, the rent in 80128 increased by $350
4. How much has the rent in 80128 increased/decreased in the last month?
In the last month, the rent in 80128 decreased by $10
5. How many available rentals are there in 80128?
There are currently 52 rentals available in 80128.
6. How do rent prices in 80128 compare with the national average?
The average rent in 80128 is $2,750 — Infinity% higher the national average of $0.